I. Am. Red. Cyclone.

I decided to do some studying out of sheer boredom.

In various instruction manuals released with the various versions of Street Fighter II that have been released since 1991, it was stated somewhere that Zangief learned his signature Spinning Piledriver Attack on accident.

According to the legend, he was sucked inside a tornado while out in the Russian wilderness while he was in the process of piledriving a bear, as he always has done previously.

Zangief's stats say that he is 7 feet tall and weighs 350 LBS. To give you an idea how large that is, his closest real life counterpart in terms of height and weight would be Paul Wight, also known as The Giant and The Big Show in various professional wrestling circles. The current stats have him listed as 7 feet tall and weighing in at 485 LBS. Anyone who has seen him perform (including myself) can testify that his size is almost unreal.

Now, the most common species of bear in the Soviet Union/Russian Federation would be the Eurasian Brown Bear. A full-grown male usually comes in at 460 LBS at most and 8 feet tall standing on it's hind legs. Assuming that Zangief would be facing off against a bear of that size, their combined weight would be 810 LBS.

Zangief has been shown in every single game that he has ever been in that he is able to piledrive his opponents far beyond his own height. Since it's extremely hard to calculate exactly how much, we'll say just for the sake of argument that he usually piledrives his opponent up to 17.5 feet. That's two and a half times his own height.

Now, here comes the part I need help on. I don't know what formula to use to determine how much force it would take to launch 810 LBS up to 17.5 feet in the air. Math has never been my forté.

Can The Internet solve this?